Mathematics 04: Independence and Bayes' Theorem — Questions, Formulas, and Answers
Mathematics 04: Independence and Bayes’ Theorem
Question 1 — Are two coin flips independent?
Flip a fair coin twice. Does the first result change the chance of heads on the second flip?
No. The second coin flip does not remember the first one.
Independence formula
A and B are independent when:
P(A ∩ B) = P(A) × P(B)
For two heads:
P(first head ∩ second head) = 1/2 × 1/2 = 1/4
The chance is 25%.
Question 2 — Are drawing two aces without replacement independent?
Draw one card from a standard deck. Keep it out. Then draw another card.
The first result changes the deck for the second result, so the events are not independent.
P(first ace) = 4/52
P(second ace given first ace) = 3/51
P(two aces) = 4/52 × 3/51 = 1/221
This uses the multiplication rule for dependent events:
P(A ∩ B) = P(A) × P(B | A)
P(B | A) means “the probability of B, given that A already happened.”
Question 3 — What is Bayes’ theorem?
A medical test can be positive or negative. A positive result is evidence, but it is not automatically proof that a person has the disease.
Bayes’ theorem tells us how to update a probability when we receive evidence.
Bayes’ theorem
P(A | B) = P(B | A) × P(A) / P(B)
| Symbol | Meaning |
|---|---|
A |
the claim we want to know about |
B |
the evidence we observed |
P(A) |
probability of A before new evidence: prior |
P(A | B) |
probability of A after evidence B: posterior |
Worked question — a positive medical test
Suppose:
- 1% of people have a disease:
P(disease) = 0.01 - The test correctly finds the disease 99% of the time:
P(positive | disease) = 0.99 - It incorrectly gives a positive result to 5% of healthy people:
P(positive | healthy) = 0.05
Question: If a test is positive, what is the chance the person has the disease?
First find the chance of any positive result. This is the total probability rule:
P(positive) = P(positive | disease) × P(disease)
+ P(positive | healthy) × P(healthy)
P(positive) = 0.99 × 0.01 + 0.05 × 0.99
= 0.0594
Now use Bayes:
P(disease | positive) = 0.99 × 0.01 / 0.0594
= 0.1667
A positive result means about a 16.67% chance of disease in this example. The probability is not 99% because the disease is rare and false positives exist.
Formula summary
Independent events: P(A ∩ B) = P(A)P(B)
Dependent events: P(A ∩ B) = P(A)P(B | A)
Bayes' theorem: P(A | B) = P(B | A)P(A) / P(B)
Total probability: P(B) = Σ P(B | Aᵢ)P(Aᵢ)
Practice
A website detects fraud. 2% of transactions are fraudulent. The detector catches 90% of fraud and incorrectly flags 4% of legitimate transactions. Find P(fraud | flagged).
Answer
P(flagged) = 0.90 × 0.02 + 0.04 × 0.98 = 0.0572
P(fraud | flagged) = (0.90 × 0.02) / 0.0572 ≈ 0.3147
About 31.47% of flagged transactions are actually fraudulent.